WEBAUTHENTICATIONDETAILS CANNOT BE CAST TO

This way I can have all the informations I need about the logged in user. By clicking “Post Your Answer”, you acknowledge that you have read our updated terms of service , privacy policy and cookie policy , and that your continued use of the website is subject to these policies. What stacktrace do you get? Sign up using Facebook. I am using Spring Security in my application. Sign up or log in Sign up using Google.

MyUserDetails] with root cause java. By clicking “Post Your Answer”, you acknowledge that you have read our updated terms of service , privacy policy and cookie policy , and that your continued use of the website is subject to these policies. I also considered the approach of extending the spring’s User class and overloading the constructor of my User class. Have you created an overloaded constructor in MyUserDetails? Sign up using Email and Password. To fix this I referred to this article.

But after referring to the article I removed the setting of GrantedAuthorities from here and moved it to my User class. Post Your Answer Discard By clicking “Post Your Answer”, you acknowledge that you have read our updated terms of serviceprivacy policy and cookie policyand that your continued use of the website is subject to these policies. I need loggedIn user details in the controllers of my application. I also considered the approach of extending the spring’s User class and overloading the constructor of my User class.

Can anyone advice me the correct approach to obtain the user class info in the controllers? Sign up or log in Sign up using Google. MyUserDetails] with root cause java. Xaerxess I have added spring version and stacktrace and I am using Java config.

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Webauthenticationdetalls Required, but never shown. Security Config class there is no change in this. By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand webauthenticationdetaiils Terms of Service.

What version of Spring do you use? To fix this I referred to this article. By clicking “Post Your Answer”, you acknowledge that you have read our updated terms of serviceprivacy policy and cookie policyand that your continued use of the website is subject to these policies. I am using Spring Security in my application. But then every time I initialize my User anywhere in the code I have to provide all the constructors parameters which webauthenticationndetails not good at all.

I am not sure how to map this property to the database.

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By cannt “Post Your Answer”, you acknowledge that you have read our updated terms of serviceprivacy policy and cookie policy webauthenticwtiondetails, and that your continued use of the website is subject to these policies. Have you created an overloaded constructor in MyUserDetails? Stack Overflow works best with JavaScript enabled.

Stack Overflow works best with JavaScript enabled. Yes I overloaded the constructor. This question is answered here but then two I am getting error, don’t know where I am missing. Do you still have the ClassCastException?

Org.springframework.security.core.userdetails.User нельзя передать в MyUserDetails

Post Your Answer Discard By clicking “Post Your Answer”, you acknowledge that you have read our updated terms of serviceprivacy policy and cookie policyand that your continued use of the website is subject to these policies. Sign up using Facebook. I have taken mkyong tutorial to add additional data in MyUserDetails In my case email id.

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My Spring security version is less than 3. The existing User table schema doesn’t contain a GrantedAuthority column besides It’s not even a primitive type.

java – нельзя передать в MyUserDetails – Qaru

I have similar “requirements” as you and for my it is working fine. Sign up using Facebook. User cannot be cast to com. Cannott Required, but never shown. I am getting class cast exception when I implement User class of spring security. Thank You very much your hint worked for me and I am posting full code if in case some one facing the same issue it would be easy for him. Implemented spring-security UserDetails class in my User class. You don’t “need” to do that, your code should work.

Thank You all for your time and efforts. Post as a guest Name.

My guess is that your problem is with auth. What stacktrace do you get? Post as a yo Name. I want to add few additional details in MyUserDetails id but I am not able to get the result. Deinum Aug 28 ’15 at I am using Hibernate for object mapping.